(adsbygoogle = window.adsbygoogle || []).push({}); Ok i have always wanted to make my own calculator that doesn't use the method that only uses one operator e.g + or -, that is all it does. but my program asks the user to input there own operator e.g +.

heres the code i was on about at the start (the plain boring one) BTW I'm using Dev C++ because i can make an executable for you guys

    #include <cstdlib>

#include <iostream>



using namespace std;



int main(int argc, char *argv[])

{

    double value1;

    double value2;

    double result;

    

    cout << "Put two boring numbers in and ill only use +" << endl;

    

    cin >> value1;

    cout << "+" << endl;

    cin >> value2;

    

    result = value1 + value2;

    

    cout << "= " << result << endl;

    

    

    system("PAUSE");

    return EXIT_SUCCESS;

}

now here is the strong advanced one =D

    #include <iostream>

#include <cstdlib>



using namespace std;



int main()

{

    double value1;

    double value2;

    double result;

    char oOperator;





    cout << "Enter a number then a operator and then another number! e.g \n1+1, 1x1, 1/1, 1-1 (x + / -) \a \n";



    cin >> value1;

    cin >> oOperator;

    cin >> value2;



    switch (oOperator)

    {

        case 'x':

        case 'X':

        case '*':

        {

            result = value1 * value2;

            cout << result;

            break;

        }



        case '+':

        {

            result = value1 + value2;

            cout << result;

            break;

        }



        case '-':

        {

            result = value1 - value2;

            cout << result;

            break;

        }



        case '/':

        {

            result = value1 / value2;

            cout << result;

            break;

        }



        default:

        {

            cout << "!!!Was that a mathmatical symbol?!!!";

            break;

        }

    }

    cout << "\n";

    _sleep(1000);



    system("PAUSE");

    return 0;

}

tell me what you guys think also the download link it below.

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, the calculator should loop, also try integrating functions.

well i tried to to a goto loop and when i done that the whol program kept bleeping like mad and would close tried to end the process that didnt works untill i click restart then aborted the restart so it closed the program.

Now try and make it a scientific calculator so that you can just type in a binomial like 4+5 and it will only accept an int as the first variable, a char as the second and another int as the third. After you accompish that try moving into unknown polynomials like 4+5+6 or 4-5+6*7

Here's a simple calculator i just wrote:

    

// calculator

#include <iostream>

#include <string>



using namespace std;



#define charToInt(x) ((int) (x)-4

#define intToChar(x) ((char) (x)+4



int main() {

	string calcString;

	

	puts("Enter string: ");

	getline(cin, calcString);

	

	int result = charToInt(calcString[0]);

	

	for(int i = 0; i < calcString.length(); i++) {

		if(calcString[i] == '+' {

			result += charToInt(calcString[i+1]);

		}

		else if(calcString[i] == '-' {

			result -= charToInt(calcString[i+1]);

		}

		else if(calcString[i] == '*' {

			result *= charToInt(calcString[i+1]);

		}

		else if(calcString[i] == '/' {

			result /= charToInt(calcString[i+1]);

		}

		else if(calcString[i] == '%' {

			result %= charToInt(calcString[i+1]);

		}

	}

	cout << "Result: " << result << "\n\n";

	return 0;

}

Dont ever use goto commands, they are not good and are pointless.

what should i use instead? while?

while(x==y)
{
}

Ok thanks :arate:

The code inside {} will only loop if the test expression (x==y) evaluates to true.