All Possible Solutions:
1+1+11
1+2+10
1+3+9
1+4+8
1+5+7
1+6+6
2+2+9
2+3+8
2+4+7
2+5+6
3+4+6
3+5+5
3+6+4
3+7+3
4+5+4

Products of Ages:
1x1x11=11
1x2x10=20
1x3x9=27
1x4x8=32
1x5x7=35
1x6x6=36
2x2x9=36
2x3x8=24
2x4x7=15
2x5x6=60
3x4x6=72
3x5x5=75
3x6x4=72
3x7x3=63
4x5x4=80

60 and up are a bit ridiculous to be an airplane seat number.

Possible answers:
1,6,6
2,2,9

If the seat number had been anything different, he would have been able to give the ages without needing additional info.

Since he says the "oldest child" we can assume there are not two older children.

This only leaves:
2,2,9



I saw a similar problem on google while trying to figure out any clues as to what was going on with this problem. You must login or register to view this content. (If you find that to be cheating, then you in no way need to pay me )

Ok.
Same princple but I screwed up the math with the possible combinations.
We know that the oldest child is a single so we can rule out twin combinations above 4.
If you work out all of the possible combinations of twins and singles to sum 13 you come up with only 2 similar product totals
1+1+11 = 13 product is 11
1+6+6 = 13 prodcut is 36
2+2+9 = 13 product is 36 ( the seat number )
4+4+5 = 13 product is 40
3+3+7 = 13 product is 42
I could keep going on with the possible combinations but the only 2 similar products is 36 and because there is an single older it must be 2+2+9

Of course I am probably wrong and about to look like a flamming ass.

WINRAR! .



You were beaten by a matter of seconds :carling:.

Two men on a plane ride are having a conversation. The first man asks if the other has any children, to which he replies, "Yes, I have three children."

The first man asks for the ages of the three children. The seconds responds with, "The sum of their ages is thirteen."

The first man says, "That's not enough information."

The second man says, "The product of their ages is the same as my seat number."

The first man thinks for a little bit, but then replies with, "That's still not enough information."

The second man says, "One last clue. My oldest child is afraid of spiders."


What are the ages of the three children?


FIRST PERSON TO GET THE CORRECT ANSWER GETS 100,000 VBUX

I will not respond to any answers that lack an explanation.

All Possible Solutions:
1+1+11
1+2+10
1+3+9
1+4+8
1+5+7
1+6+6
2+2+9
2+3+8
2+4+7
2+5+6
3+4+6
3+5+5
3+6+4
3+7+3
4+5+4

Products of Ages:
1x1x11=11
1x2x10=20
1x3x9=27
1x4x8=32
1x5x7=35
1x6x6=36
2x2x9=36
2x3x8=24
2x4x7=15
2x5x6=60
3x4x6=72
3x5x5=75
3x6x4=72
3x7x3=63
4x5x4=80

60 and up are a bit ridiculous to be an airplane seat number.

Possible answers:
1,6,6
2,2,9

If the seat number had been anything different, he would have been able to give the ages without needing additional info.

Since he says the "oldest child" we can assume there are not two older children.

This only leaves:
2,2,9



I saw a similar problem on google while trying to figure out any clues as to what was going on with this problem. You must login or register to view this content. (If you find that to be cheating, then you in no way need to pay me )