(adsbygoogle = window.adsbygoogle || []).push({}); You must login or register to view this content.

You must login or register to view this content.

I am stuck at #3,A, down. I dont even know where to start. All help is appreciated.

I took one look at this lol! I struggle doing basic maths, nevermind this! :derp:

For the second one its PK=PK due to the reflection prop.
the third one KPA= PKR due to 2 congruent angles therefore Congruent Triangles
and the way you prove the parts congruent is due to CPCTC
now for the second problem I don't really feel like doing that one

If we're assuming ABC IS a triangle then:
First we need to prove that the two smaller triangles are congruent. We can see from the given facts that they each have 2 equivilent angles. Since all angles in any triangle must add up to give 180, the other angle of each triangle must also be equal. Now, this proves that the triangles are SIMILAR but it doesnt prove that they are congruent. To do that we need to prove one more thing. All you need to do is say that side BD is a shared side and is therefore equal. This proves that the triangles are congruent via Angle,side,angle equivilency proof. The next step is you say BA = BC because corresponding side lengths in congruent triangles are equivilent.

Sorry i see that was two days ago... most likely no longer relavent but it might help you or some one else lol... if you have any more question please post them ill do my best to answer them

you NERDS i would never know how to work that out

I'll help you get started on #3. <ADB and <CDB are congruent and supplementary, making them equal to 90 degrees. The top two angles are congruent also. Through some type of substitution, the two base angles are congruent as well. Therefore, the triangle is isosceles, and BA is congruent to BC.

This was posted on the 5th, I think your a little late as far as homework goes. :dumb: