(adsbygoogle = window.adsbygoogle || []).push({}); What would be a way so that you can type in a word into a wordbox, and the website returns how many people also put that word?

(question in simplest form)

I am not asking for the entire coding or what not, just the way it would be done.
Don't tell me that if I am asking then I am not able.
get back to me?

hmmm this is a gaming site so i doubt most of the CHILDREN on here known. some might dont get me wrong but why dont chu pop into the shoutbox of the site on my sig , im sure someone can help you .

1. Why would I join another forum?
2. Your website is down.
3. NGU is surprisingly useful.

1. so your telling me your only part of 1 forum
2. nev3er down. mods think there funny and changed the link , try again
3. i agree with you. i have some good friends on here

Use SQL to create a data base, when they input the word, add it to the data base, make sure you have a primary ID key, when displaying how many people used that word, do a SQL search for all rows containing the word, and use a for loop to cycle through each result adding an increment to a variable that will finally output the amount of people who have, you could also add a 3rd field to add there IP address to filter out multiple inputs, or just add a cookie, which is easier but means it won't always work.

Thanks
Still learning how to make the database

I would make a table like said before, and then just count the table rows.

Example:

Table something like so:

    

CREATE TABLE IF NOT EXISTS `word` (

`id` int(11) NOT NULL AUTO_INCREMENT,

PRIMARY KEY (`id`)

) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=0;

Now you would have a table. That would go up. So form something like this.

    

if(isset($_POST['done']))

{

	//Change to whatever your page is ofcourse. And we also view the amount of times.

	$amount = mysql_query("SELECT COUNT(id) FROM word");

	print 'Word sumbited '.$amount.' times.';

	//Now this is what would be the query to insert it into the page if the word is whatever you want.

	//For example we will submit the word "Bama"

	//First check if word is Bama. This example is case sensitive.

	if($_POST['done'] == "Bama")

	{

		//This might not work.....As the submit is NULL because the table I made

		//Is just an ID.

		mysql_query("INSERT INTO word () VALUES ()");

	}

}

else

{

	//Change the form to however you want.

	print '<form action="'.$_SERVER['PHP_SELF'].'" method="post">

	<input type="text" name="done" value="" />

	<input type="submit" value="Submit" />

	</form>";

}