Post: Can someone verify this statement
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02-18-2013, 01:48 AM
#1
|C++|
< ^ > < ^ >
int main(){int *gg=Function();.............}
[B][I][U]int *Function()[/U][/I][/B]
{
int x=3;
int *pointer=x;
return *pointer;
}
(im talking about the "int *Function()" part)
im just trying to solidify my understanding.
02-18-2013, 09:58 PM
#2
Originally posted by SLiiTH3R
in c++ the reason for making a function type pointer like this is so that we can initialize the return value to a pointer type. And if it was a reference "&" instead of pointer type we would be initializing the return value to reference type.
(im talking about the "int *Function()" part)
im just trying to solidify my understanding.
int main(){int *gg=Function();.............}
[B][I][U]int *Function()[/U][/I][/B]
{
int x=3;
int *pointer=x;
return *pointer;
}
(im talking about the "int *Function()" part)
im just trying to solidify my understanding.
How can you express the pointer from int to int*..? That would need a conversion of a different dimension if I'm not wrong.
Compile:
invalid conversion from 'int' to 'int*'
02-19-2013, 09:53 PM
#3
|C++|
< ^ > < ^ >
Originally posted by LEzStarz
How can you express the pointer from int to int*..? That would need a conversion of a different dimension if I'm not wrong.
Compile:
Compile:
invalid conversion from 'int' to 'int*'
actually it was supposed to be a pointer *gg which is then set to gg=whatever()
where as 'int *soldier::setAmmo()' returns an address of a variable. Which does compile. This is why i really didnt need someone to compile the code for me, i could have done that mself. I wanted to know the reasoning behind the int * name part of the code.
pro tip:Microsoft word will never tell you why you spell somehting wrong. Neither will your compiler.(Even though the code i wrote on my compiler was'nt wrong, just saying)
02-20-2013, 05:56 AM
#4
Jakes625
Guest
I'm assuming you mean.
because:
int *function() doesnt have a return variable for the type.. if you're trying to pass data to an arguement then you can do so by the following..
idk what you're trying to do though. so I hope this helped in some way lol.
int *gg Function()
{
return *item;
}
because:
int *function() doesnt have a return variable for the type.. if you're trying to pass data to an arguement then you can do so by the following..
int main()
{
int a = 2;
function( a );
cout<<a<<endl;
cin.get();
return 0;
}
function( int &n )
{
return (n + 3);
}
idk what you're trying to do though. so I hope this helped in some way lol.
02-24-2013, 05:48 AM
#5
|C++|
< ^ > < ^ >
Originally posted by Jakes625PS3
I'm assuming you mean.
because:
int *function() doesnt have a return variable for the type.. if you're trying to pass data to an arguement then you can do so by the following..
idk what you're trying to do though. so I hope this helped in some way lol.
int *gg Function()
{
return *item;
}
because:
int *function() doesnt have a return variable for the type.. if you're trying to pass data to an arguement then you can do so by the following..
int main()
{
int a = 2;
function( a );
cout<<a<<endl;
cin.get();
return 0;
}
function( int &n )
{
return (n + 3);
}
idk what you're trying to do though. so I hope this helped in some way lol.
nvm i found out a while ago that all it means is that you are return ing a pointer type/ref. simple
02-27-2013, 12:13 AM
#9
|C++|
< ^ > < ^ >
Originally posted by Jakes625PS3
tbh, I don't even know what that is myself. well at least the term anyway.
so your in the process of learning c++ too? In that case we should collab and talk to eachother more, i hear its good to have a friend who is also learning c++ at around the same level as you. It provides motivation and you can help eachother in the learning process.
02-27-2013, 01:55 AM
#10
Jakes625
Guest
Originally posted by C
so your in the process of learning c++ too? In that case we should collab and talk to eachother more, i hear its good to have a friend who is also learning c++ at around the same level as you. It provides motivation and you can help eachother in the learning process.
If you want. lol.
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