(adsbygoogle = window.adsbygoogle || []).push({}); So i have a homework due next week and i havent started it, so i wanted some suggestions on how to even start at it.
Basically what I have to do is:

    Read a fraction of the form a/b from the keyboard, reduce it to its lowest form, and print the answers. user enters 2/4 program prints 1/2



Details:

Prompt for a fraction, and then read the input from the keyboard. 

Validate input, print a error message if invalid & allow for fraction to be re-entered.

Numerator & denominator are 32-bit signed integers.

The output must be a fraction of the form a/b. 6/3 will be printed as 2/1.

    Sample Program:



    enter a fraction to reduce: this isnt a fraction

    Invalid Input bro.

    

    enter a fraction to reduce: 2/10

    

    Here is your fraction: 1/5

notes: the teacher said to use this algorithim:

    int GCD(int a, int b) {

        if(b==0) 

            return a;

        else

            return GCD(b, a % b);

        }

its called the Euclid algorithim. its everywhere online, so that shouldnt be the hard part.

anyway, any help?
---------------------------
now i need my program to just check for valid inputs and i'm done. any help?

    

#include <stdio.h>

int getfraction(int n, int m)

{

	int getfraction, remainder; 

	while (n != 0)

	{

		remainder = m % n;

		m = n;

		n = remainder;

	}

	getfraction = m;

	return getfraction;

}

 

int main (int argc, const char * argv[]) {

	int num1, num2;

	int newNum1, newNum2;

	char yesno;



for(;

{	

	printf("Enter a fraction you wish to reduce: ");

	scanf("%d/%d", &num1, &num2);

	newNum1 = num1 / getfraction(num1, num2);

	newNum2 = num2 / getfraction(num1, num2);

	printf("Your Fraction Reduces to: %d/%d \n", newNum1, newNum2);

	printf("Do you want to reduce another fraction?(y/n): \t ");

	scanf("%s", &yesno);

	if (yesno == 'n'

	{break;}

}}

Why do professors start with C? They should drop straight into C++ or start with a high level language such as Python.

idk my college starts with java then assembly language, now i'm taking a course that includes C and c++.

why not just do:
int num, den;
scanf("%d /%d", &num, &den);

scanf returns the number of arguments it filled in. so all you have to do is check if it's less than 2 to see if it's bad input.

updated my program. any help?

YES! You know whats up!