Post: Good maths problem!
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09-13-2010, 06:50 AM
#1
xOMANx
Can’t trickshot me!
What is the four digit number in which the first digit is 1 quater of the last digit, the second digit is 6 times the first digit, and the third digit is the second digit plus three?
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Congrats Juko18!! You got it right!!!
09-14-2010, 06:34 PM
#11
TheManDavid
Your mother!
09-14-2010, 06:58 PM
#12
Anal Treat
NGU's resident prick
09-14-2010, 07:02 PM
#14
Anal Treat
NGU's resident prick
The following user thanked Anal Treat for this useful post:
09-14-2010, 07:35 PM
#17
Anal Treat
NGU's resident prick
09-14-2010, 07:37 PM
#18
elfmotat
Rᵤᵥ - ½gᵤᵥR ∝ Tᵤᵥ
Originally posted by FionnDawg
So Intregal of Sin x squared?
Well you have to change the sin(x^2) to it's double angle side.
The doubled angle side of sin(x^2) is 1-Cos(x2). Then because of the intregal, We do 1/2. So this is now 1/2 1-cos(x2).
Am I close?
Well you have to change the sin(x^2) to it's double angle side.
The doubled angle side of sin(x^2) is 1-Cos(x2). Then because of the intregal, We do 1/2. So this is now 1/2 1-cos(x2).
Am I close?
It's not sin²(x), it's sin(x²). The x is squared, not the sine function so identities don't work.
Originally posted by DESTRUCTINATOR
You differentiate using the chain rule i believe.
No.
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