Post: 500k vBux Challenge
01-19-2011, 01:50 AM #1
elfmotat
Rᵤᵥ - ½gᵤᵥR ∝ Tᵤᵥ
(adsbygoogle = window.adsbygoogle || []).push({}); I will be giving 500,000 vBux to the first person to answer correctly.


The Problem

Originally posted by another user
There exists a spherical planet about the size of the Earth with a uniform density of 5000 kg/m³. A hole (negligible mass removed) is drilled through the diameter of the planet so that objects can be dropped and freely fall. A bowling ball is lowered into the hole to a height of 1,000,000 m above the center of the planet where it is released from rest. How far away is the ball from where it was released after 3 hours? (Assume the planet is completely at rest.)


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01-19-2011, 05:40 AM #20
italianboss
☆Level 1 Trustworthy☆
Originally posted by elfmotat View Post
I haven't gotten any pm's Eek.


i just sent it to you
01-19-2011, 06:43 AM #21
+tA. Rick
Former Staff
Originally posted by elfmotat View Post
I haven't gotten any pm's Eek.


Originally posted by italianboss View Post
i just sent it to you


I believe you sent it to me by accident. :carling:

The following user thanked +tA. Rick for this useful post:

elfmotat
01-19-2011, 07:14 AM #22
a-4 + (h2o) = 19-s2 ? Happy
01-19-2011, 02:07 PM #23
NeedaLifeSoon
Retired Life
Originally posted by elfmotat View Post
I haven't gotten any pm's Eek.


I'll give you 500 K to stop making me feel stupid!!!

How about 18,000M above sea level, because of the lava spout.

Or it doesn't move at all?
01-19-2011, 07:57 PM #24
I suck at my maths :(
01-19-2011, 08:07 PM #25
MY POOR HEAD ! , Im gonna get this , KOF KOF Honest LOL
01-19-2011, 08:13 PM #26
elfmotat
Rᵤᵥ - ½gᵤᵥR ∝ Tᵤᵥ
I wonder if this looks familiar to anyone...

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01-20-2011, 01:02 AM #27
elfmotat
Rᵤᵥ - ½gᵤᵥR ∝ Tᵤᵥ
Alright, well this doesn't really seem to be garnishing the enthusiasm I hoped it would... so I may just post the solution.

Respond if you object to me doing to before next Tuesday.
01-20-2011, 06:41 AM #28
elfmotat
Rᵤᵥ - ½gᵤᵥR ∝ Tᵤᵥ
Solution is now posted.

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