Originally posted by thinkcentre12ba
i am trying to sovle for x
log 3^x - log3(x+3) = 4
this problem i just cant solve i tried putting the log3/x+3 but i know it is not right so idk what to do please help
thanks
From what I can re-call...
log 3^x - log3(x+3) = 4
log 3 ^ x(x+3) =4
x(x+3) = 3 ^ 4
x^2 + 3x = 81
x^2 + 3x -81 = 0
Do the quadratic formula from there and the positive solution is your answer..I think.
-3 +- the square root of [9 -4(1)(-81)]
But if you do that, you get a negative, meaning the answer is imaginary... so either an answer with i or no solution.. Haven't done these in ages.