Post: Some Fun Math
02-15-2011, 12:48 AM #1
thinkcentre12ba
Do a barrel roll!
(adsbygoogle = window.adsbygoogle || []).push({}); i am trying to sovle for x

log 3^x - log3(x+3) = 4

this problem i just cant solve i tried putting the log3/x+3 but i know it is not right so idk what to do please help



thanks
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02-15-2011, 12:51 AM #2
ZoneHD
Shiver do you lift?
Originally posted by thinkcentre12ba View Post
i am trying to sovle for x

log 3^x - log3(x+3) = 4

this problem i just cant solve i tried putting the log3/x+3 but i know it is not right so idk what to do please help



thanks


Since when was math fun?

I dont understand any of this LOL

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thinkcentre12ba
02-15-2011, 12:52 AM #3
thinkcentre12ba
Do a barrel roll!
Originally posted by ZoneHD View Post
Since when was math fun?

I dont understand any of this LOL


math is always fun hahah. it is just some problems just through you for a loop.
02-15-2011, 12:53 AM #4
Solo
Rookie
When in doubt, use the FOIL method.

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thinkcentre12ba
02-15-2011, 12:53 AM #5
TrytoYOLO
We all <3 Amanda
log (3^x/3x+9) ... i think
02-15-2011, 12:54 AM #6
log 3^x - log 3(x+3) = 4
log ((3^x)/(3x+3)) = 4
thats how far i got, all i know is when you divide logs, you have to take log common and divide the first log by the second log, i think maybe the question is wrong, can u recheck the question?
Im thinking the questions should be
log 3^x - log 3^x+3 = 4
02-15-2011, 12:56 AM #7
thinkcentre12ba
Do a barrel roll!
Originally posted by Shooter View Post
When in doubt, use the FOIL method.


if it was like log7(x-6)+log7(x+3) i would FOIL it but since this only has log3(x+3) i wasn't sure what to do
02-15-2011, 12:57 AM #8
Math isn't fun.
Especially this. >_<
02-15-2011, 12:59 AM #9
thinkcentre12ba
Do a barrel roll!
Originally posted by Mr.Deagle View Post
log 3^x - log 3(x+3) = 4
log ((3^x)/(3x+3)) = 4
thats how far i got, all i know is when you divide logs, you have to take log common and divide the first log by the second log, i think maybe the question is wrong, can u recheck the question?
Im thinking the questions should be
log 3^x - log 3^x+3 = 4


it looks like this log3^x - log3(x+3) = 4 but i do see what you meant the x+3 should be rised maybe it was a mistake in the book. because when the ^x+3 is like that then it is easier to solve
02-15-2011, 01:02 AM #10
Originally posted by thinkcentre12ba View Post
it looks like this log3^x - log3(x+3) = 4 but i do see what you meant the x+3 should be rised maybe it was a mistake in the book. because when the ^x+3 is like that then it is easier to solve


yeh, only if i saw this problem a couple months back, i did these kinds in advanced functions but its semester two and now its calculus time and we focusing on limits, shows how much you can forget in a small amount of time lol

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