(adsbygoogle = window.adsbygoogle || []).push({}); I need help, here is what the problem is: Consider the expression: 1 + (6/7 + (2+3)*4)*5 The problem contains these operations: 3 additions 2 multiplications(*) 1 division and 2 sets of parentheses. The task: Keeping the numbers in their original order of 1 6 7 2 3 4 5, rearrange the operations to find the maximum value of the expression and then rearrange it to find the minimum value. I need the to see the work involved in this. IF YOU GET THIS FOR ME I WILL GIVE 300k

You have to use 3+ 2x 1/ and 2() or can it be like (1 + 6 + 7 + 2 + 3 + 4) x 5?

No you cant do that lol I asked my teacher you have to have 3+ 2x 1/ and 2()

Solve the Parentesis then Multiplications & Divisions, Thats all you need to do bro

No, thats not the end of it though I have to rearrange the operations to find the highest possible value and the rearrange them to find the lowest value.

3 + (2/1+(4+5)*6)*7=465
Max?
5 + (7/6 + (4+3)*2)*1=20.1666666
Lowest?

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Max and lowest?

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Fuk, original order, damn...

Yeah lol its harder than you think :y:

Im on my iPad now...its hard if I had my TI94+ I could do it in 5 minutes...

Ugh lol, well if you can get it by this Thursday then thats fine.

I'll try tomorrow... Fuk school! I start thursday...