Post: Maths Thread
02-02-2012, 11:45 PM #1
(adsbygoogle = window.adsbygoogle || []).push({}); For the smarter folk of NGU. Answer one then post one.

1+2i
------ <======== It's a fraction i.e 1+2i OVER 2-i
2-i

i^2 = -1

Write the answer as a+bi. Where a and b are both digits.

GO !
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02-05-2012, 03:15 AM #2
glitchplz
Samurai Poster
Originally posted by MCPADDINGTON View Post
For the smarter folk of NGU. Answer one then post one.

1+2i
------ <======== It's a fraction i.e 1+2i OVER 2-i
2-i

i^2 = -1

Write the answer as a+bi. Where a and b are both digits.

GO !


(1+2i)/(2-i)=i

Is the following nonsingular:

0 1 5 7 6 9
4 5 3 0 1 7
0 0 0 0 0 0
1 1 2 8 9 4
1 4 5 3 2 4
9 6 3 2 1 4
02-05-2012, 03:43 AM #3
sunce99
League Champion
i am going to University this September , I am only 16 & i don't get that xD
02-05-2012, 04:08 AM #4
Originally posted by MCPADDINGTON View Post
For the smarter folk of NGU. Answer one then post one.

1+2i
------ <======== It's a fraction i.e 1+2i OVER 2-i
2-i

i^2 = -1

Write the answer as a+bi. Where a and b are both digits.

GO !



I got 0+1i (in a+bi form), but that would just be i.
02-05-2012, 04:13 AM #5
The correct answer is

1 + ((2 * i) / 2) - i = 1

because you are dividing the 2's and the i's so you are only left with a 1
02-05-2012, 10:56 AM #6
Originally posted by glitchplz View Post
(1+2i)/(2-i)=i

Is the following nonsingular:

0 1 5 7 6 9
4 5 3 0 1 7
0 0 0 0 0 0
1 1 2 8 9 4
1 4 5 3 2 4
9 6 3 2 1 4


..........................no.

Originally posted by sunce99 View Post
i am going to University this September , I am only 16 & i don't get that xD


I'm not in university yet either, this the most basic maths question I could find on my course, where do you live? Must have a poor education system...

Originally posted by Different View Post
The correct answer is

1 + ((2 * i) / 2) - i = 1

because you are dividing the 2's and the i's so you are only left with a 1


You can't divide by 2 if it's a fraction in which 2 of the 4 numbers aren't divisible by 2. Besides I told you to give the answer in the form of a+bi.

Originally posted by Travis View Post
I got 0+1i (in a+bi form), but that would just be i.


DING ! DING ! DING ! We have a winner !

For everyone else, these are called complex numbers:

(1+2i) / (2-i) * (2+i) / (2+i) // The division of two complex numbers is defined in terms of complex multiplication.

(2+i+4i+2i^2) / (4+2i-2i-i^2) // Remember i^2 = -1. Now just add the real numbers together and the imaginary unit i together.

(5i) / (5) // Now divide top and bottom by 5.

Answer: 0+i

Link to complex numbers on Wikipedia = You must login or register to view this content.

Ok a new relatively easy one.

f(x) = x^2-7x+12

If f(x+1) is not equal to 0, find f(x) / f(x+1). Answer in the form of (x-a) / (x-b). Find the values of a and b.
02-05-2012, 11:03 AM #7
sharangan11
Do a barrel roll!
allow quandratics this early LOL
02-05-2012, 06:58 PM #8
sunce99
League Champion
Originally posted by MCPADDINGTON View Post
..........................no.



I'm not in university yet either, this the most basic maths question I could find on my course, where do you live? Must have a poor education system...



You can't divide by 2 if it's a fraction in which 2 of the 4 numbers aren't divisible by 2. Besides I told you to give the answer in the form of a+bi.



DING ! DING ! DING ! We have a winner !

For everyone else, these are called complex numbers:

(1+2i) / (2-i) * (2+i) / (2+i) // The division of two complex numbers is defined in terms of complex multiplication.

(2+i+4i+2i^2) / (4+2i-2i-i^2) // Remember i^2 = -1. Now just add the real numbers together and the imaginary unit i together.

(5i) / (5) // Now divide top and bottom by 5.

Answer: 0+i

Link to complex numbers on Wikipedia = You must login or register to view this content.

Ok a new relatively easy one.

f(x) = x^2-7x+12

If f(x+1) is not equal to 0, find f(x) / f(x+1). Answer in the form of (x-a) / (x-b). Find the values of a and b.


In the UK.....

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