Originally posted by glitchplz
(1+2i)/(2-i)=i
Is the following nonsingular:
0 1 5 7 6 9
4 5 3 0 1 7
0 0 0 0 0 0
1 1 2 8 9 4
1 4 5 3 2 4
9 6 3 2 1 4
..........................no.
Originally posted by sunce99
i am going to University this September , I am only 16 & i don't get that xD
I'm not in university yet either, this the most basic maths question I could find on my course, where do you live? Must have a poor education system...
Originally posted by Different
The correct answer is
1 + ((2 * i) / 2) - i = 1
because you are dividing the 2's and the i's so you are only left with a 1
You can't divide by 2 if it's a fraction in which 2 of the 4 numbers aren't divisible by 2. Besides I told you to give the answer in the form of a+bi.
Originally posted by Travis
I got 0+1i (in a+bi form), but that would just be i.
DING ! DING ! DING ! We have a winner !
For everyone else, these are called complex numbers:
(1+2i) / (2-i) * (2+i) / (2+i) // The division of two complex numbers is defined in terms of complex multiplication.
(2+i+4i+2i^2) / (4+2i-2i-i^2) // Remember i^2 = -1. Now just add the real numbers together and the imaginary unit i together.
(5i) / (5) // Now divide top and bottom by 5.
Answer: 0+i
Link to complex numbers on Wikipedia =
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Ok a new relatively easy one.
f(x) = x^2-7x+12
If f(x+1) is not equal to 0, find f(x) / f(x+1). Answer in the form of (x-a) / (x-b). Find the values of a and b.