Originally posted by hellzoom
i have been googling this for about an hour and i cannot find a cheatsheet for the textbook im in grade 10 and i failed gr.9 math cuz i missed half the year last year and if i dont finish this for homework i will be switched into the remidial class i just came back after vacation and he says it need to be done by tomorrow please help me im giving all my vbux away!!!
i need answers for textbook called (pearson math 9)
its a book from the (pearson mathematics series)
please i beg of u i need the answers pleeaseee
Hey I got the answer for you.
"page 72 question 2 a rectangle has an area of 36 m2.
which dimensions will ensure that the rectangle has the minimum perimeter
a. 6m by 6m b. 9 m by 4 m c. 12 m by 3m d. 18m by 2m"
The area of a rectangle is length x width right? And perimeter of a rectangle is (2 x length) + (2 x width).
The area of the rectangle is 36m2. There's lots of ways to get 36m2. But you gotta pick from A, B, C, or D. Since perimeter is 2 times the length and 2 times the width, then you're gonna have to multiply everything by 2 to get the perimeter, and the lowest one is the answer.
A) Length = 6m
Width = 6m
Perimeter = [(2 x 6m) + (2 x 6m)] = 24m
B) Length = 9m
Width = 4m
Perimeter = [(2 x 9m) + (2 x 4m) = 26m
C) Length = 12m
Width = 3m
Perimeter = [(2 x 12m) + (2 x 3m)] = 33m
D) Length = 18m
Width = 2m
Perimeter = [(2 x 18m) + (2 x 2m)] = 40m
The answer would be "A) 6m x 6m" because it's the lowest perimeter.