Post: Help with Algebra problem, due at 10 pm central time
03-01-2014, 02:34 AM #1
ic0de
Hurah!
(adsbygoogle = window.adsbygoogle || []).push({}); Can someone please help me with this math problem, as I could really use the help. Where x and y are non-negative real numbers. r, the exponent of x, is: s, the exponent of y, is:

[ATTACH=CONFIG]30040[/ATTACH]
(adsbygoogle = window.adsbygoogle || []).push({});
03-01-2014, 12:26 PM #2
Balcombeex
Bounty hunter
I might be able to help you out, but I can't view the image... Not too sure why :/
03-01-2014, 12:47 PM #3
Joel
[move]Sal:madsal::laim:[/move]
Originally posted by x View Post
I might be able to help you out, but I can't view the image... Not too sure why :/


Right click the image, open in new tab.
03-01-2014, 01:04 PM #4
-SuperMan
Krazy Weed
Is The Dot a Multiplier or what exactly.
03-01-2014, 10:13 PM #5
AgentJon
Former Staff
Originally posted by ic0de View Post
Can someone please help me with this math problem, as I could really use the help. Where x and y are non-negative real numbers. r, the exponent of x, is: s, the exponent of y, is:

[ATTACH=CONFIG]30040[/ATTACH]



Did I do this right lol.

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I have a math solver app and I can any problem, but I might need more info on what answer you're looking for if that isn't right.
03-01-2014, 10:40 PM #6
Gehirnstaub
I’m too L33T
Originally posted by Agentjon View Post
Did I do this right lol.

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I have a math solver app and I can any problem, but I might need more info on what answer you're looking for if that isn't right.

Could u maybe say the Name of the App? :-)
03-01-2014, 10:48 PM #7
AgentJon
Former Staff
Originally posted by Gehirnstaub View Post
Could u maybe say the Name of the App? :-)


It's called College Algebra Solved!
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The following user thanked AgentJon for this useful post:

Gehirnstaub
03-01-2014, 10:59 PM #8
Jango
I love my kitteh
Originally posted by Agentjon View Post
Did I do this right lol.

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I have a math solver app and I can any problem, but I might need more info on what answer you're looking for if that isn't right.


I am pretty sure this is correct. There are 3 x's and it is cubed so therefore you need 3 x's to be able to pull one x out.


Use this answer op.

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