(adsbygoogle = window.adsbygoogle || []).push({}); If anyone can solve some of these problems for me I'd love you! This is for a summer assignment for next year btw, I'm not in summer school. please show some of your work. I can't just put the actual answers. I've done about half of these (50 question totals), but I don't have my math book because my dumb school made me turn it back in and I can't find anything remotely useful on Google.

4. Given f(x)= {x^2; x (is less than or equal to) -2
{3x+5; x> -2

find:

a) f(-6) b) f(-2) c) f(0) d) f(10)

5. Given f(x)= x^2 + 3 and g(x) = 4x-1, find:

a) (f-g)(x)
b) (f+g)(x)
c) f(x) x g(x)
d) f of g(x)
e) g of f(x)
f)f(x)/g(x)
g)f(g(2))
h)g(f(2))

6. Find the inverse function of f(x)= 3x-7

7. Write in standard form (a+bi): 4i/1+3i

9. Find all the zeros of: f(x)= x^3-7x^2+11x+19

11. Solve for (x,y)

x+2y=1
5x-4y=-23

13. Given y=x^2-4x+3,

a) write in standard form
b) find vertex
c) find equation of the axis of symmetry
d)find the x-intercepts
e)find the y-intercept

17. Use properties of logarithms to condense:

4lnx-5lny

18. Use properties of logarithms to expand:

log2(3a^4)

*The 2 is lower and by the g again, can't type it like that though.

19. Solve:

3^x = 81

4^x = 27

20. Simplify

(3x^-7y^10/51x^4y^7)^-2

So you are asking us to do your homework.

You know you can look these problems up on the Internet bud and they will tell you how to do it or they will do it for you.

Pfft.. easy! Do it yourself.

This is Pre-Calc/Calculus stuff, correct? I was in Pre-Calc last year, going into Calculus this year.

The way you wrote number 4 is confusing to me.

Number 5
a) Do f(x) - g(x)
So: x^2-3-4x+1 (plus 1 because you have to distribute the negative)
x^2-4x-2
Do that for the two below it too.
d) Replace any x's in f(x) with the g(x) equation
So: (4x-1)^2+3
16x^2-8x+1
For the next one put the f(x) equation into g(x)
f) Just put f(x) over g(x) and simplify it
g) Do g(2) first
So: 4(2)-1=7
Now do f(7)
So: (7)^2+3=52
For the next one, do the same thing, except you start with f(x)

Number 6
For the inverse, just swap x and y (f(x))
So: x=3y-7
3y=x+7
y=x+7 all over 3
Remember to replace y with f(x) when finished
So: f(x)=x+7 all over 3

I need some time to remember 7 and 9

Number 11
This one is very easy. Use elimination.
x+2y=1
5x-4y=-23
Multiply the first equation by 2, so you can get the y value to 4, so you can eliminate the y value.
So: 2(x+2y=1)
2x+4y=2
The subtract the -4y from the second equation.
So: 2x=2
Therefore x=2
Now substitute the x value in any equation you want. I'll go with the first equation.
So: (2)+2y=1
2y=-1
y=-1/2

13, 17, and 18 I don't quite remember, I'll keep thinking though.

Number 19
This one is also very easy. This is pretty much stuff that should be in your head, and if it's not, it's a simple guess and check process with your calculator.
3^x=81
3^4=81
4^x=27
Hm, this one is a little more tricky. I will need to think about it.

I can't figure out what you wrote for number 20. Put parentheses around the exponents please?

Will update when I figure more out.

You should get a casio calculator. All of these can be directly done with that calc. It is THE biggest time saver!

I have a TI-84 graphing calculator. What does Casio do that makes it good?

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Well, you don't have to now. But I'll find you. Eventually. And make you do it then.

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I do, but they are always like majorly different, or have a small difference, but it makes a big difference in the outcome.

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Heres a pic of how #4 is exactly asked:

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Forum doesn't make it easy to write some of these.

And thanks for the ones you did.

Number 4
f(-6): Since -6 is less than -2, we will use the first equation.
So: (-6)^2-1=35

Use the first equation for -2 as well, because -2 is equal to -2. Use the second equation for the other two.

Heres my awesome paint skillz for $20, once again the forum limits how well you can erect math problems.

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Much better.

Number 20
This is simple, really. First off, since the outside exponent is a negative, let's swap the numerator and denominator. We now have:

(51x^4 y^7) ^2
------------
(3x^-7 y^10)

Now, lets get rid of that negative x exponent. Move it to the denominator, making it positive, so simply add 7 and 4.

(51x^11 y^7) ^2
-------------
(3y^10)

Now multiply all the exponents in the parentheses by two, as well as squaring any numbers.

(2601x^22 y^14)
-----------------
(9y^20)

Now simplify.

289x^22 y^-6

I'm only 75% sure this is right, though. I will double check on some paper.

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Just did it on paper, looks good to me.